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5^2+3^2=c^2
We move all terms to the left:
5^2+3^2-(c^2)=0
We add all the numbers together, and all the variables
-1c^2+34=0
a = -1; b = 0; c = +34;
Δ = b2-4ac
Δ = 02-4·(-1)·34
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{34}}{2*-1}=\frac{0-2\sqrt{34}}{-2} =-\frac{2\sqrt{34}}{-2} =-\frac{\sqrt{34}}{-1} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{34}}{2*-1}=\frac{0+2\sqrt{34}}{-2} =\frac{2\sqrt{34}}{-2} =\frac{\sqrt{34}}{-1} $
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